The correct option is C 5x+2y=10
Let's take the ordered pairs from the graph and check.
Let's consider the equation 5x+2y=10 first.
The ordered pair (0,5) indicates x=0 and y=5 .
Plug in these values into the equation. we get
5(0)+2(5) =10
⇒ 0+10= 10
⇒ 10= 10
⇒ LHS= RHS.
So, the ordered pair (0,5) satisfy the equation.
The ordered pair (2,0) indicates x=2 and y=0 .
Plug in these values into the equation. we get
5(2)+2(0) =10
⇒ 10+0= 10
⇒ 10= 10
⇒ LHS= RHS.
So, the ordered pair (2,0) satisfy the equation.
Both of these ordered pairs do not satisfy other equations.