Which of the following equilibriums degree of dissociation is independent of initial concentration?

H I ⇌ \frac{1}{2} H_{2} + \frac{1}{2} I_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P C l_{5} ⇌ P C l_{3} + C l_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N_{2} O_{4} ⇌ 2 N O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

all the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $H I ⇌ \frac{1}{2} H_{2} + \frac{1}{2} I_{2}$
Dissociation reactions in which $Δ n = 0$ , degree of dissociation is independent of inital concentration.
For the equilibirum , equilibirum constant expression can written as,
$H I ⇌ \frac{1}{2} H_{2} + \frac{1}{2} I_{2}$
$K = \frac{C α}{C (1 - α)} = \frac{α}{1 - α}$

Suggest Corrections

Similar questions

P C l_{5} (α)

P C l_{5} ⇌ P C l_{3} + C l_{2}

α << 1

P {C l}_{5} (α)

P {C l}_{5} ⇌ P {C l}_{3} + {C l}_{2}

α = {[K_{p} / (P + K_{p})]}^{1 / 2}

P C l_{5} ⇌ P C l_{3} + C l_{2}

α

P C l_{5} (α)

P C l_{5} ⇌ P C l_{3} + C l_{2}

Join BYJU'S Learning Program