Which of the following exhibit geometrical isomerism (M stands for metal, and a and b are achiral ligands)?

M a_{2} b_{2} (S q . P I .)

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M a_{4} b_{2}

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M a_{5} b

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M a_{6}

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Solution

The correct options are
A $M a_{2} b_{2} (S q . P I .)$
B $M a_{4} b_{2}$
Square planar $M a_{2} b_{2}$ and octahedral $M a_{4} b_{4}$ show geometrical isomerism.
They exist in cis and trans forms. Geometrical isomerism is not possible in the complexes $M a_{5} b a n d M a_{6}$ .

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Similar questions

Which of the following statements is correct regarding the chirality (optical isomerism) of the cis and trans isomers of the type $M (a a)_{2} b_{2}$ (M stands for a metal, a and b are achiral ligands and aa is a bidentate ligand) ?

Q. Which of the following octahedral complex does not show geometrical isomerism (A and B are monodentate ligands)?

Q. Which one of the following octahedral complexes will not show geometrical isomerism?(A and B are monodentate ligands )

Q. Which of the following square planar complex does not show geometrical isomerism?

AA is symmetrical bidentate ligand
AB is unsymmetrical bidentate ligand
a and b are monodentate ligands

Q. Which of the following square planar complexes will show cis-trans isomerism?

[M is the metal while a and b are monodentate ligands.]

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Which of the following exhibit geometrical isomerism (M stands for metal, and a and b are achiral ligands)?

The correct options are A Ma2b2(Sq.PI.) B Ma4b2Square planar Ma2b2 and octahedral Ma4b4 show geometrical isomerism.They exist in cis and trans forms. Geometrical isomerism is not possible in the complexes Ma5bandMa6.

The correct options are
A $M a_{2} b_{2} (S q . P I .)$
B $M a_{4} b_{2}$
Square planar $M a_{2} b_{2}$ and octahedral $M a_{4} b_{4}$ show geometrical isomerism.
They exist in cis and trans forms. Geometrical isomerism is not possible in the complexes $M a_{5} b a n d M a_{6}$ .