Which of the following exhibits both inductive effect and hyperconjugation?

C H_{3} - C H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} - C H_{2} - C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} - (C H)_{2}^{+}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $C H_{3} - (C H)_{2}^{+}$
$C H_{3} - (C H)_{2}^{+}$ will show hyperconjugation due to the presence of H-atoms of $C H_{3} -$ group and also, it will show inductive effect due to the absence of symmetry.

Suggest Corrections

Similar questions

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

S_{N} 2

c o n c . H C l :

(a) C H_{3} - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{2} - C l

(b) C H_{3} - C H_{3} | C | C H_{3} - C H_{2} O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{1} | C | C H_{3} - C H_{2} - C H_{3}

(c) C H_{3} - O H | C | C H_{3} - C H_{3} A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C l | C | C H_{3} - C H_{3}

(d) C H_{2} = C H - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{2} = C H - C H_{2} - C l

\begin{matrix} C H_{3} - & C H & - C H_{2} - C l | C H_{3} \end{matrix}

\begin{matrix} C H_{3} - C H_{2} - & C H & - C l | C H_{3} \end{matrix}

S_{N} 1

(i) C H_{3} - + C H - C H_{2} - O C H_{3}

(i i) C H_{3} - + C H - C H_{2} - C H_{3}

(i i i) C H_{3} - + C H - O | | C - C H_{3}

Join BYJU'S Learning Program