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Hydrides of Nitrogen

Which of the ...

Question

Which of the following exhibits highest solubility in $H_{2} O$ :

N H_{3}

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P H_{3}

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A s H_{3}

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S b H_{3}

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Solution

The correct option is A $N H_{3}$
As the size of the nitrogen in ammonia( $N H_{3}$ ) is small when compared to the central atoms of other hydrides of the 5th group, so it is most electro-negative atom and forms a strong hydrogen bonding with water molecules and dissolve more(solubility is high).
Hence option A is correct.

Suggest Corrections

Similar questions

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

S i F_{4} < S i C l_{4} < S i B r_{4} < S i I_{4}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3}, P H_{3}, A s H_{3}

S b H_{3}

N H_{3}, P H_{3}, A s H_{3}, S b H_{3}

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