A - B K 2 K 1- C K 3 DWhich of the following expression is-are correct-A- d - C - dt - K 1- A - B -B- d - C - dt 1- K 1- A - B - K 2- C - K 3- D -C- - d - A - dt - K 1- A - B - K 2- C -D- d - D - dt - K 3- C -

The correct options are B d[C]/dt =K_1 [A][B] K_2 [C] K_3 [D] C d[A]/dt=K_1 [A][B] K_2[C] D d[D]/dt=K_3[C] These are elementary reactions Appearance of C ⇒d[ ...

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Byju's Answer

Standard XII

Chemistry

Elementary and Complex Reactions

A + B K 2 K 1...

Question

Which of the following expression is/are correct?

$\frac{d [C]}{d t} = K_{1} [A] [B]$

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$\frac{d [C]}{d t} = K_{1} [A] [B] - K_{2} [C] - K_{3} [D]$

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$\frac{- d [A]}{d t} = K_{1} [A] [B] - K_{2} [C]$

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$\frac{d [D]}{d t} = K_{3} [C]$

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Solution

The correct options are
B
$\frac{d [C]}{d t} = K_{1} [A] [B] - K_{2} [C] - K_{3} [D]$

C
$\frac{- d [A]}{d t} = K_{1} [A] [B] - K_{2} [C]$

D
$\frac{d [D]}{d t} = K_{3} [C]$

These are elementary reactions

Appearance of $C \Rightarrow \frac{d [C]}{d t} = K_{1} [A] [B] - K_{3} [D] - K_{2} [C]$

Disappearance of $A \Rightarrow \frac{- d [A]}{d t} = K_{1} [A] [B] - K_{2} [C]$

Appearance of $D \Rightarrow \frac{d [D]}{d t} = K_{3} [C]$

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Similar questions

Q. For the reaction

2 A \to B + 3 C; i f - \frac{d [A]}{d t} = k_{1} [A]^{2}; \frac{d [B]}{d t} = k_{2} [A]^{2}; \frac{d [C]}{d t} = k_{3} [A]^{2}

the correct reaction between

k_{1}, k_{2} a n d k_{3}

is :

Q. For the reaction

2 A ⟶ B + 2 C

; if

- \frac{d [A]}{d t} = k_{1} [A]^{2}

;

- \frac{d [B]}{d t} = k_{2} [A]^{2}

;

- \frac{d [C]}{d t} = k_{3} [A]^{2}

the correct relation between

k_{1}

k_{2}

and

k_{3}

is :

Q. For the reaction

2 A \to B + 3 C

; if

- \frac{d [A]}{d t} = k_{1} [A]^{2}; \frac{d [B]}{d t} = k_{2} [A]^{2}; \frac{d [C]}{d t} = k_{3} [A]^{2}

the correct relation between

k_{1}, k_{2}

and

k_{2}

is:

Q. For the reaction

2 A ⟶ B + 3 C

; if

- \frac{d [A]}{d t} = k_{1} {[A]}^{2}; \frac{d [B]}{d t} = k_{2} {[B]}^{2}; \frac{d [A]}{d t} = k_{3} {[A]}^{2}

the correct relation between

k_{1}, k_{2}

and

k_{3}

Q. For a reaction,

N_{2} O_{5} ⟶ 2 N O_{2} + \frac{1}{2} O_{2}

Given:

\frac{- d [N_{2} O_{5}]}{d t} = k_{1} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k_{2} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k_{3} [N_{2} O_{5}]

The relation between

k_{1}, k_{2}

and

k_{3}

are:

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Which of the following expression is/are correct?

The correct options are B d[C]dt=K1[A][B]−K2[C]−K3[D] C −d[A]dt=K1[A][B]−K2[C] D d[D]dt=K3[C] These are elementary reactions Appearance of C⇒d[C]dt=K1[A][B]−K3[D]−K2[C] Disappearance of A⇒−d[A]dt=K1[A][B]−K2[C] Appearance of D⇒d[D]dt=K3[C]