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Vectors and Its Types

Which of the ...

Question

Which of the following expression is equal to zero.

\to A \times \to A

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\to A . (\to A \times \to B)

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\to B \times [\to A \times (\to A \times \to B)]

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^i \times (^j \times^k)

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Solution

The correct options are
A $\to A \times \to A$
D $^i \times (^j \times^k)$
$\to A \times \to A = 0$
$& ˆ i \times (ˆ j \times ˆ k) = 0$
Hence,
option $(A)$ and $(D)$ is correct answer.

Suggest Corrections

Similar questions

\to a =^i +^j, \to b =^i +^k

{{(\to a \times \to b) \times \to a} \times \to a} \times \to b =

^i \times [(\to a \times \to b) \times^i] + ¯ j \times [(\to a \times \to b) \times^j] + ¯ ¯ ¯ k \times [(\to a \times \to b) \times^k]

\to a =^i +^j +^k

\to b = - 3^i +^k

\to c =^i + 2^j + 3^k

A)

[\to a \times \to b

\to b \times \to c

\to c \times \to a]

B)

[\to a + \to b

\to b + \to c

\to c + \to a]

C)

[\to a

\to b

\to c]

[\to a

\to b

\to c]^{- 1}

D)

[\to a - \to b

\to b - \to c

\to c - \to a]

\to a =^i - 2^j +^k, \to b =^j +^k

\to r \times \to a = \to b \times \to a

\to r \times \to b = \to a \times \to b

\to a =^i +^j +^k

\to b =^i -^j +^k

\to c =^i +^j -^k

\to a =^i -^j -^k

(\to a \times \to b) \times (\to c \times \to d)

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