Which of the following expressions is equal to ${- 2^{4} + (4^{2})^{3}} ?$

16 + 4^{9}

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16 + 4^{6}

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- 16 + 4^{8}

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- 16 + 4^{6}

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Solution

The correct option is D $- 16 + 4^{6}$
$2^{4} = 2 \times 2 \times 2 \times 2 = 16$
$(4^{2})^{3} = 4^{2 \times 3} = 4^{6}$
${- 2^{4} + (4^{2})^{3}} = - 16 + 4^{6}$
So, $- 16 + 4^{6}$ is the expresion equivalent to ${- 2^{4} + (4^{2})^{3}}$

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