The correct options are
A Bond order
B π− bonding
C State of hybridization
If the bond order increases, the bond length decreases, i.e., only the sigma bond has a longer bond length than multiple bonds (sigma bond + pi bond).
Pi bonding involves double and triple bonds, bond length is shorter in case of a triple bond as it has a higher bond order.
More the percentage s character, more will be the nuclear attraction on the valence orbital due to higher penetration power of s orbital. Therefore closer overlapping orbitals lead to shorter bond length.
Thus, option (a), (b) and (c) are correct.