Which of the following figures does not represent 1 mole of dioxygen gas at STP?

(a) 16 g of gas (b) 22.4 L of gas

(c) 6.022 $\times 10^{23}$ dioxygen molecules (d) 11.2 L of gas

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Solution

Answers: (a) 16 g of gas and (d) 11.2 L of gas

It is known that, 1mole of a gas=gram molecular mass= Avogadro's number of molecules =22.4 L at STP

Thus, 1 mole of $O_{2}$ gas =32 g of $O_{2}$ =6.02 $\times 10^{23}$ molecules= 22.4L of $O_{2}$ at STP

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Which of the following figures does not represent 1 mole of dioxygen gas at STP? (a) 16 g of gas (b) 22.4 L of gas (c) 6.022 ×1023 dioxygen molecules (d) 11.2 L of gas

Answers: (a) 16 g of gas and (d) 11.2 L of gas It is known that, 1mole of a gas=gram molecular mass= Avogadro's number of molecules =22.4 L at STP Thus, 1 mole of O2 gas =32 g of O2=6.02 ×1023 molecules= 22.4L of O2 at STP

Which of the following figures does not represent 1 mole of dioxygen gas at STP?

(a) 16 g of gas (b) 22.4 L of gas

(c) 6.022 $\times 10^{23}$ dioxygen molecules (d) 11.2 L of gas

Answers: (a) 16 g of gas and (d) 11.2 L of gas

It is known that, 1mole of a gas=gram molecular mass= Avogadro's number of molecules =22.4 L at STP

Thus, 1 mole of $O_{2}$ gas =32 g of $O_{2}$ =6.02 $\times 10^{23}$ molecules= 22.4L of $O_{2}$ at STP