Question

Which of the following fractions are having the lowest form as $\frac{1}{3}$?

• A. $\frac{3}{9}$
• B. $\frac{4}{8}$
• C. $\frac{4}{12}$
• D. $\frac{2}{8}$

Answer 1

Answer: (A), (C)

The correct options are
A $\frac{3}{9}$
C $\frac{4}{12}$

To convert the given fractions in it's lowest form, we divide both the numerator and the denominator with the same number.


$\frac{3}{9}=\frac{\frac{3}{3}}{\frac{9}{3}}$ = $\frac{1}{3}$

$\frac{4}{8}=\frac{\frac{4}{4}}{\frac{8}{4}}$ = $\frac{1}{2}$

$\frac{4}{12}=\frac{\frac{4}{4}}{\frac{12}{4}}$ = $\frac{1}{3}$

$\frac{2}{8}=\frac{\frac{2}{2}}{\frac{8}{2}}$ = $\frac{1}{4}$


Simplest form of $\frac{3}{9}$ & $\frac{4}{12}$ is $\frac{1}{3}$.