Question

Which of the following fractions lie between $\frac{3}{8}$ and $\frac{7}{8}$ on the number line?

• A. $\frac{1}{2}$
• B. $\frac{1}{4}$
• C. $\frac{20}{16}$
• D. $\frac{9}{8}$

Answer 1

The correct option is A

$\frac{1}{2}$

We need to find a fraction $\frac{p}{q}$ from the given options such that $\frac{3}{8}<\frac{p}{q}<\frac{7}{8}$.

In order to compare the given fractions, let's make the denominator same (i.e. 8) for all.

​$\frac{1\times 4}{2\times 4}=\frac{4}{8}$

​$\frac{1\times 2}{4\times 2}=\frac{2}{8}$

​$\frac{20÷2}{16÷2}=\frac{10}{8}$

and $\frac{9}{8}$ already has 8 in the deominator.

Now, if we compare the numerators we can see that $3<4<7$, therefore $\frac{4}{8}$ i.e. $\frac{1}{2}$ lies between $\frac{3}{8}$ and $\frac{7}{8}$.