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Question

Which of the following functions are even and which are odd?

1) f(x)=x2+7
2) f(x)=x+2
3) f(x)=x7+2x5
4) f(x)=|x|+4

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Solution

When f(x)=f(x), function is even
f(x)=f(x), function is odd

(A)
f(x)=x2+7
f(x)=x2+7 - Even

(B)
f(x)=x+2
f(x)=x+2 - Neither even nor odd
(C)
f(x)=x72x5
f(x)=x72x5- odd

(D)
f(x)=|x|+4
f(x)=|x|+4 - Even







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