Which of the following functions are not identical?
A
f(x)=lnx2 and g(x)=2lnx
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B
f(x)=logxe and g(x)=1logex
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C
f(x)=sin(cos−1x) and g(x)=cos(sin−1x), x∈(0,1)
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D
None of these
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Solution
The correct option is Af(x)=lnx2 and g(x)=2lnx Only Option one is not identical since f(x)=logx2 has a domain (−∞,0)⋃(0,∞) while f(x)=2logx has a domain (0,∞)