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Question

Which of the following functions are not identical?

A
f(x)=lnx2 and g(x)=2lnx
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B
f(x)=logxe and g(x)=1logex
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C
f(x)=sin(cos1x) and g(x)=cos(sin1x), x(0,1)
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D
None of these
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Solution

The correct option is A f(x)=lnx2 and g(x)=2lnx
Only Option one is not identical since
f(x)=logx2 has a domain (,0)(0,) while f(x)=2logx has a domain (0,)

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