The correct options are
A 15−(x−1)15
C x7+x5+2x3+2
Since all the term in f(x)=x7+x5+2x3+2 contain odd powers with a+ sign all the terms in f′(x),im(x) in any odd differential coefficient are positive with even power of x .
∴ any odd differential coefficient of f(x) cannot be zero.
15−(x−1)15 is a decreasing function .