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Law of Reciprocal

Which of the ...

Question

Which of the following functions is non – injective?

f (x) = | x + 1 |, x ϵ [- 1, \infty)

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g (x) = x + \frac{1}{x}, x ϵ (0, \infty)

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h (x) = x^{2} + 4 x - 5, x ϵ (1, \infty)

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k (x) = e^{- x}, x ϵ [0, \infty)

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Solution

The correct option is B $g (x) = x + \frac{1}{x}, x ϵ (0, \infty)$
Clearly, (a) Increasing.
(b) Neither increasing nor decreasing
(c) Increasing
(d) Decreasing

Suggest Corrections

Similar questions

f (x) = x + \frac{1}{x}; x \in (0, \infty)

g (x) = x^{2} + 4 x - 5; x \in (0, \infty)

f (x) = x^{2} + \frac{1}{x^{2}} and g (x) = x - \frac{1}{x}, x ϵ R - {- 1, 0, 1}, and h (x) = \frac{f (x)}{g (x)}

h (x)

A = \{x : - 1 \leq x \leq 1\}

f (x) = \frac{x}{2}

g (x) = \sin (\frac{π x}{2})

h (x) = | x |

k (x) = x^{2}

f (x) = 4 x - 5, g (x) = x^{2}

h (x) = \frac{1}{x}

f (g (h (x)))

f (x) = x^{2} + \frac{1}{x^{2}}

g (x) = x - \frac{1}{x},

x \in R - {- 1, 0, 1} .

h (x) = \frac{f (x)}{g (x)},

h (x)

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