Which of the following Gaussian surface is not useful?

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(a) and (b) both.

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Solution

The correct option is B
The Gaussian surface is useful for the following points:
( $1$ ) Gauss law is always applicable to any closed surface.
( $2$ ) But the useful Gaussian surface is symmetrical about charge/charge distribution.

Based on these observations, we can see that the Gaussian surface in option (b) is not symmetrical about charge distribution.
Hence, option (b) is correct.

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