Which of the following gives a reddish brown precipitate with $N a O H$ solution?

F e S O_{4}

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F e_{2} (S O_{4})_{3}

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C u S O_{4}

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M n S O_{4}

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Solution

The correct option is A $F e_{2} (S O_{4})_{3}$
Ferric sulphate reacts with sodium hydroxide to form a reddish brown precipitate of ferric hydroxide.
The reaction is as follows:
$F e_{2} (S O_{4})_{3} + 6 N a O H \to 2 F e (O H)_{3} ↓ + 3 N a_{2} S O_{4}$

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