Which of the following gives $B_{2} H_{6}$ on reaction with ${N a B H}_{4}$ .

L i A l H_{4}

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N a O H

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I_{2}

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None

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Solution

The correct option is C $I_{2}$
$N a B H_{4} (s) + I_{2} \to B_{2} H_{6} (g) + N a l (s) + H_{2}$
Balanced equation
$2 N a B H_{4} (s) + I_{2} \to B_{2} H_{6} (g) + 2 N a l (s) + H_{2}$

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