Which of the following gives $C l_{2}$ gas at an anode and $H_{2}$ gas at cathode on electrolysis?

Concentrated solution of

N a C l

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Molten

N a C l

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Dilute solution of

N a C l

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Solid

N a C l

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Solution

The correct option is A Concentrated solution of $N a C l$
The electrolysis of a concentrated aqueous solution of NaCl gives $C l_{2}$ gas at the anode and $H_{2}$ gas at the cathode.
Reduction of water at cathode: $2 H_{2} O (l) + 2 e^{-} \to H_{2} (g) + 2 O H^{-} (a q)$
Oxidation of chloride ions at anode: $2 C l^{-} (a q) \to C l_{2} (g) + 2 e^{-}$

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Similar questions

H_{2}

C l_{2}

C l_{2}

H_{2} O

List -I	List -II
(i) Dilute solution of $H C l$	(P) $O_{2}$ evolved at anode
(ii) Dilute solution of $N a C l$	(Q) $H_{2}$ evolved at cathode
(iii) Concentrate solution of $N a C l$	(R) $C l_{2}$ evolved at anode
(iv) Fairly concentrate solution of $A g N O_{3}$	(S) $A g$ deposition at cathode

Which of the following option has the incorrect combination considering List-I and List-II

Column 1 Column II

A) Dilute solution of $H C l$ (P) $O_{2}$ evolved at anode

B) Dilute solution of $K C l$ (Q) $H_{2}$ evolved at Cathode

C) Concentrate solution of $N a C l$ (R) $C l_{2}$ evolved at anode

D) Fairly concentrate solution of $A g N O_{3}$ (S) Ag deposition at cathode

which gas is evolved at cathode during electolysis of an aqueus solution of Nacl?

H_{2}

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