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Ideal Gas Equation

Which of the ...

Question

Which of the following gives equivalent mass of $N a_{2} C O_{3}$ when titrated against $H C l$ in the presence of methyl orange?

A

5.3

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B

53

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C

10.6

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D

106

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Solution

The correct option is B $53$
$N a_{2} C O_{3} + 2 H C l M e t h y l o r a n g e - -------- \to 2 N a C l + H_{2} O + C O_{2}$
Equivalent mass $=$ molecular mass $/ 2 = 106 / 2 = 53$ .

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Similar questions

Q. Calculate the equivalent mass of

N a_{2} C O_{3}

when it is titrated against

H C l

in presence of phenolphthalein.

10 g

N a_{2} C O_{3}

N a O H

was titrated against

H C l

by using phenolphthalein followed by adding methyl orange after first equivalence point,

7.7818 g

H C l

was consumed in total. Find the mass of

N a_{2} C O_{3}

in the mixture.

40

0.05 M

solution of sesqui-carbonate

(N a_{2} C O_{3} . N a H C O_{3} .2 H_{2} O)

is titrated against

0.05 M

H C l

x

H C l

is used when phenolphthalein is the indicator and

y

H C l

is used when methyl orange is the indicator in two separate titrations. Hence,

(y - x)

20

0.1 M

solution of compound

N a_{2} C O_{3} . N a H C O_{3} .2 H_{2} O

is titrated against

0.05 M H C l, x m L

H C l

is used when phenolphthalein is used as an indicator and

y m L

H C l

is used when methyl orange is the indicator in two separate titrations. Hence

(y - x)

20

0.1 M

solution of compound

N a_{2} C O_{3} . N a H C O_{3} .2 H_{2} O

, is titrated against

0.05 M H C l . x

H C l

is used when phenolphthalein is used as an indicator and

y

H C l

is used when methyl orange is the indicator in two separate titrations. Hence,

(y - x)

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