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Hyperconjugation

Which of the ...

Question

Which of the following gives most stable carbocation on dehydration?

C H_{3} C H_{2} C H_{2} C H_{2} O H

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C H_{3} - C H - C H_{2} - O H | C H_{3}

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C H_{3} | C H_{3} - C - O H | C H_{3}

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C H_{3} | C H_{3} - C - C H_{2} - C H_{2} - O H | C H_{3}

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Solution

The correct option is C $C H_{3} | C H_{3} - C - O H | C H_{3}$
Tertiary alcohol will give stable tertiary carbocation.

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Similar questions

C H_{3} - C | C H_{3} H - C H_{2} - C H_{2} - O H

C H_{3} - O H | C | C H_{3} - C H_{2} - C H_{3}

C H_{3} C H_{3} | C H - O H | C H - C H_{3}

A, B, C

S_{N} 2

c o n c . H C l :

(a) C H_{3} - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{2} - C l

(b) C H_{3} - C H_{3} | C | C H_{3} - C H_{2} O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{1} | C | C H_{3} - C H_{2} - C H_{3}

(c) C H_{3} - O H | C | C H_{3} - C H_{3} A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C l | C | C H_{3} - C H_{3}

(d) C H_{2} = C H - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{2} = C H - C H_{2} - C l

C H_{3} - O H | C H - C H_{2} - C H_{3} A l_{2} O_{3} - -- \to 573 K C H_{3} - C H = C H - C H_{3}

C H_{3}

C H_{3}

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C H_{3} - C - C H_{2} - B r + N a O H ⟶ C H_{3} - C - C H_{2} - C H_{3}

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C H_{3}

O H

C H_{3} - C H = C H - C H_{3} H_{3} O^{+} - -- \to C H_{3} - C H_{2} - O H | C H - C H_{3}

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