Which of the following gives the correct arrangement of compounds based on their bond strength ?

H F > H C l > H B r > H I

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H I > H B r > H C l > H F

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H F > H B r > H C l > H I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H C l > H F > H B r > H I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $H F > H C l > H B r > H I$
Electronegativity plays a role, but there is an even bigger effect. As you go down a group, the shell number (n) increases, meaning that the outer valence electrons (the ones to make that bond with hydrogen) are further and further away from the nucleus.

The bigger the element, the less "tightly" it can hold onto the hydrogen.

Suggest Corrections

Similar questions

H F, H C l, H B r, H I

The correct order of thermal stability of hydrogen halides (H – X) is

The correct order of the thermal stability of hydrogen halides (H -X) is

H F, H C l, H B r, H I

H I, H B r, H C l

H F

Join BYJU'S Learning Program