Question

Which of the following gives the maximum number of isomers ?

• A. $\left[Co\right(N{H}_3{)}_{4}C{l}_2]$
• B. $\left[Ni\right(en\left)\right(N{H}_3{)}_4{]}^{2+}$
• C. $\left[Ni\right(C_2{O}_4\left)\right(en{)}_2]$
• D. $\left[Cr\right(SCN{)}_2(N{H}_3{)}_4{]}^{+}$

Answer 1

The correct option is D $\left[Cr\right(SCN{)}_2(N{H}_3{)}_4{]}^{+}$

$\left[Cr\right(SCN{)}_2(N{H}_3{)}_4{]}^{+}$ gives maximum number of isomers.

These includes cis trans isomers and linkage isomers.

In cis isomer, two SCN ligands are adjacent and in trans isomers, they are opposite. Linkage isomerism is due to ambidentate nature of the ligand SCN as it can coordinate either through S or through N.