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Question

Which of the following graph is correct?

Λm - Molar conductivity
C - concentration of electrolyte

A
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B
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C
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D
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Solution

The correct option is C
Variation in molar conductivity of strong electrolyte due to ion-ion interaction is given by an empirical relation proposed by kohlrausch.

Λm=Λ0mAC
Λm - Molar conductivity
Λ0m - Limiting molar conductivity
C is concentration of electrolyte
A is constant for a given solvent and temperature.

Λm=Λ0mAC
This equation is in the form of straight line equation,
y=c+mx

Plot of Λm vs C



Intercept : Λ0m
Slope : A

All electrolytes of a particular type have the same value for ‘A’.
Since KCl and NaCl are of same type (equal charge on cation and anion), they have similar A value which means they have a same slope. So, their will be of parallel to each other.


Thus, graph (c) is incorrect.

KCl and MgSO4 is of different type of electrolyte, charges on cations and anions are ,
KCl +1,1MgSO4 +2,2
So they have different slope hence, they dont have a parallel lines.
Thus, graph (b) is incorrect.

In graph (d), we have CH3COOH which is a weak electrolyte. Weak electrolyte will have a rectangular parabola curve and it does not intercept the y-axis.
Thus, graph (d) is also incorrect.

Hence, graph (a) is the correct one.

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