Which of the following graph is valid for a solution containing phenol and aniline?
Assume that at the given constant temperature of solution, vapour pressure of phenol (A) in pure state is more than that of aniline (B) in pure state.

None of the above

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Solution

The correct option is D

A mixture of phenol and aniline shows negative deviation from raoult's law.
Liquids showing negative deviation will have total vapour pressure less than what it should be according to Raoult's Law because solvent-solute interaction is more than the solvent-solvent and the solute-solute interactions.
Intermolecular hydrogen bonding between phenolic proton and lone pair on nitrogen atom (in aniline) is stronger than the respective intermolecular hydrogen bonding between similar molecules.
In option (c): $P_{T} < p_{A}^{\circ} χ_{A} + p_{B}^{\circ} χ_{B}$

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