Question

Which of the following graph represent Boyle's law?

Answer 1

According to Boyle's law, for a confined gas at constant temperature, the product of pressure and volume is constant.
So, as per Boyles law
$PV=\text{constant}$
$\therefore P\propto \frac{1}{V}$
Let, $P=\frac{K}{V}....\left(1\right)$, where $K$ is any constant.
$\therefore \frac{P}{V}=\frac{K}{V^2}$
Hence plot of $\frac{P}{V}$ vs $\frac{1}{V^2}$ will give a straight line.
From equation $\left(1\right)$, $\log P=\log K-\log V$, where $K$ is any constant.
Therefore, the plot of $\log P$ vs $\log V$ is a straight line with a negative slope.