Which of the following graphs correctly represent the variation of electric field E vs r for a ring, where r represents the distance from the centre of ring along its axis.
A
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A
Electric field, →E due to a ring of radius R along its axis at distance r from its centre is given by,
|→E|=KQr(R2+r2)32
At the centre of the ring, r=0 so, |→E|=0
At r→∞ we have,
|→E|=limr→∞KQrr3(R2r2+1)32=0
Now, we know that, →E achieves its maxima at r=±R√2
On plotting the above points we get the graph as shown below.