Which of the following graphs correctly represents the variation of -d V-d p-VY with P for an ideal gas at constant temperature-

The correct option is A A. From PV= RT d.V.P + V.dp = 0 or ( nbsp;dV/dP ) nbsp;= V/P or β = nbsp;(dV/dP/V)_γ nbsp;= 1/p Thus plot of β vs P gives. ...

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Standard XI

Mathematics

f(x) transforms to f(x)+a or f(x)-a

Which of the ...

Question

Which of the following graphs correctly represents the variation of $β$ = - $(\frac{\frac{d V}{d P}}{V})_{γ}$ with P for an ideal gas at constant temperature.

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Solution

The correct option is A

A. From PV= RT d.V.P + V.dp = 0

or ( $\frac{d V}{d P}$ ) = - $\frac{V}{P}$

or $β$ = $(\frac{\frac{d V}{d P}}{V})_{γ}$ = $\frac{1}{p}$

Thus plot of $β$ vs P gives.

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Which of the following graphs correctly represents the variation of β = - (dVdPV)γ with P for an ideal gas at constant temperature.

The correct option is A A. From PV= RT d.V.P + V.dp = 0 or ( dVdP ) = - VP or β = (dVdPV)γ = 1p Thus plot of β vs P gives.

Which of the following graphs correctly represents the variation of $β$ = - $(\frac{\frac{d V}{d P}}{V})_{γ}$ with P for an ideal gas at constant temperature.

The correct option is A

A. From PV= RT d.V.P + V.dp = 0

or ( $\frac{d V}{d P}$ ) = - $\frac{V}{P}$

or $β$ = $(\frac{\frac{d V}{d P}}{V})_{γ}$ = $\frac{1}{p}$

Thus plot of $β$ vs P gives.