Which of the following graphs gives the equation $x = v_{0} t + \frac{1}{2} a t^{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
Given the equation
$x = v_{0} t + \frac{1}{2} a t^{2}$
$\Rightarrow \frac{d x}{d t} = \frac{d (v_{0} t + \frac{1}{2} a t^{2})}{d t}$
$\Rightarrow v = v_{0} + a t$
So, the $v - t$ curve can be shown as

Suggest Corrections

Similar questions

x = v_{0} t + \frac{1}{2} a t^{2}

x = v_{0} t + \frac{1}{2} a t^{2}

v - t

x = v_{0} t = \frac{1}{2} a t^{2}

v - t

x

t

v_{0}

a

x = v_{0} t + 1 / 2 a t^{2}

a

s = u t + \frac{1}{2} a t^{2}

Join BYJU'S Learning Program