Question

Which of the following graphs represent the probability density curve for 4d electrons?

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

Number of radial nodes = $n-l-1$
where, n = principal quantum number
$l$ = azimuthal quantumnumber
For 4d orbital, n = 4 and l = 2
Hence, the number of radial nodes = $4-2-1$ = 1
Also, at the nucleus i.e. r = 0, the value of $R^2$ is zero for $d$ orbital. So, the graph between $R^2$ versus r will start from zero and have minimum electron density at one place.