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Standard IX

Chemistry

Dobernier's Triads

Which of the ...

Question

Which of the following group follows Dobereiner's law of triads?

Cl,Br,I

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I,Br,Cl

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Ba,Sr,Ca

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None of the above

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Solution

The correct option is A
Cl,Br,I

Elements in Dobereiner's Triads are in the increasing order of Atomic mass and the central element has atomic mass which is equal to the average atomic mass of the other two elements. Therefore from periodic table we can find out that Option A is correct.

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Similar questions

Consider the following elements :

Ca, Cl, Na, I, Li, Ba, Sr, K, Br

Separate these elements into three groups (families) of similar properties. State one property in each case on the basis of which you have made your choice.

Q. From the set of elements given below, identify the correct order of electron affinities of the elements.
(a)

B e > M g > C a > S r > B a

(b)

F > C l > B r > I

(c)

B e > B > C > N > O

(d)

C l > F > B r > I

Q. State whether the following elements belong to a Group (G), Period (P) or Neither Group nor Period (N).

Elements	G/P/N
$L i, C, O$
$M g, C a, B a$
$B r, C l, F$
$C, S, B r$
$A l, S i, C l$
$L i, N a, K$
$C, N, O$
$K, C a, B r$

Q. Consider the following orderings:

I

A l > S i > P > C l

I I

B e < M g < C a < S r

I I I

I < B r < C l < F

I V

{N a}^{+} < {M g}^{2 +} < {A l}^{3 +} < {S i}^{4 +}

Which of these give(s) a correct trend in ionization energy?

Identify the missing elements from the following Dobereiner's triads.

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Which of the following group follows Dobereiner's law of triads?

The correct option is A Cl,Br,I Elements in Dobereiner's Triads are in the increasing order of Atomic mass and the central element has atomic mass which is equal to the average atomic mass of the other two elements. Therefore from periodic table we can find out that Option A is correct.

The correct option is A
Cl,Br,I

Elements in Dobereiner's Triads are in the increasing order of Atomic mass and the central element has atomic mass which is equal to the average atomic mass of the other two elements. Therefore from periodic table we can find out that Option A is correct.