Which of the following group of molecules have $2.5$ bond order?

N_{2}^{2 -}, O_{2}^{2 -}, C O

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N_{2}^{-}, O_{2}^{+}, N O^{2 +}

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C_{2}^{2 -}, B N, O_{2}

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C N^{-}, N O^{+}, O_{2}^{2 -}

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Solution

The correct option is B $N_{2}^{-}, O_{2}^{+}, N O^{2 +}$
$O_{2}^{+}, N_{2}^{-}, N O^{+ 2}$ are all isoelectronic with $10$ bonding electrons and $5$ antibonding electrons. So bond order is $2.5$ .

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Similar questions

Calculate the total number of molecules that will possess fractional bond order among the following molecules
$O_{2}^{2 +}, N_{2}^{2 +}, O_{2}^{+}, N O, C O, C O^{+}, O_{2}^{-}, N O^{2 +}, C N^{-}, N O^{2 -}, N_{2}^{-}$

Q. Number of paramagnetic molecules from the following are:

C N^{-}, N O, O_{2}^{2 -}, O_{2}, N O_{2}, O_{2}^{-}, B_{2}, C_{2}, F_{2}^{-}

Among the following the total no. of species which are paramagnetic

$O_{2}, S_{2}, C N^{-}, N O^{+}, O_{2}^{2 +}, O_{2}^{2 -}, B_{2}, N_{2}^{2 -}, O_{2}^{+}, N O, N O_{2}, N_{2} O$ ___

Q. Find the no. of molecules which will not exhibit sp mixing.

N O

N_{2} B_{2},, C_{2}, O_{2}, O {_{2}}^{2^{+}} O {_{2}}^{2^{-}}, N {_{2}}^{2^{+}}, N {_{2}}^{+}

Q. How many species are dimagnetic and have their bond order greater than 2.5?

N_{2}, N_{2}^{\oplus}, N O^{\oplus}, N O^{⊖}, C O, C N^{⊖}, K O_{2}, N a_{2} O_{2}

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Which of the following group of molecules have 2.5 bond order?

The correct option is B N−2, O+2, NO2+O+2,N−2,NO+2 are all isoelectronic with 10 bonding electrons and 5 antibonding electrons. So bond order is 2.5.

Which of the following group of molecules have $2.5$ bond order?

The correct option is B $N_{2}^{-}, O_{2}^{+}, N O^{2 +}$
$O_{2}^{+}, N_{2}^{-}, N O^{+ 2}$ are all isoelectronic with $10$ bonding electrons and $5$ antibonding electrons. So bond order is $2.5$ .