Which of the following haldie has maximum ionic character?

B a C l_{2}

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B e C l_{2}

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M g C l_{2}

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C a C l_{2}

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Solution

The correct option is B $B a C l_{2}$
According to the Fajan's rule, smaller the cation, bigger the anion, more is the covalent character. On the other hand, bigger cation, in the given case, will favor ionic character, as the anion is same for all. Here, $B a^{2 +}$ is the biggest cation. Hence, $B a C l_{2}$ will have maximum ionic character.

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Similar questions

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

B e C l_{2} < M g C l_{2} < C a C l_{2} < S r C l_{2} < B a C l_{2} < R a C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

B e {C l}_{2}, M g {C l}_{2}, C a {C l}_{2}

B a {C l}_{2}

L i C l

R b C l

B e C l_{2}

M g C l_{2}

B e C l_{2}, S r C l_{2}, M g C l_{2}, C a C l_{2}, B a C l_{2}

L i C l, R b C l, B e C l_{2}

M g C l_{2}

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