Which of the following halides react(s) with $A g N O_{3 (a q)}$ to give a precipitate that dissolves in $N a_{2} S_{2} O_{3 (a q)}$
(IIT-JEE, 2012)

HCl

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HBr

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Solution

The correct options are
A HCl
C HBr
D HI
$A g N O_{3} + H C l \to A g C l ↓$
$A g N O_{3} + H B r \to A g B r ↓$
$A g N O_{3} + H l \to A g I ↓$
All these precipitates will get dissolved in hypo $(N a_{2} S_{2} O_{3})$ forming complex, $N a_{3} [A g (S_{2} O_{3})_{2}]$

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Similar questions

Q. Which of the following hydrogen halides react(s) with

A g N O_{3} (a q)

to give a precipitate that dissolves in

N a_{2} S_{2} O_{3} (a q)

Q. Which of the following halides react(s) with

A g N O_{3 (a q)}

to give a precipitate that dissolves in

N a_{2} S_{2} O_{3 (a q)}

(IIT-JEE, 2012)

Q. Which of the following hydrogen halides react(s) with

A g N O_{3}

(aq) to give a precipitate that dissolves in

N a_{2} S_{2} O_{3}

(aq)?

Q. Among the following compounds, which will react with acetone to give a product containing > C = N - bond?
(IIT-JEE, 1998)

This question and the next one appeared in the in the linked comprehension format. Let's give them a shot.

An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarised in the scheme given below:
SCHEME:

M1, Q and R, respectively are

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Which of the following halides react(s) with AgNO3(aq) to give a precipitate that dissolves in Na2S2O3(aq) (IIT-JEE, 2012)

The correct options are A HCl C HBr D HIAgNO3+HCl→AgCl↓ AgNO3+HBr→AgBr↓ AgNO3+Hl→AgI↓ All these precipitates will get dissolved in hypo (Na2S2O3) forming complex, Na3[Ag(S2O3)2]

Which of the following halides react(s) with $A g N O_{3 (a q)}$ to give a precipitate that dissolves in $N a_{2} S_{2} O_{3 (a q)}$
(IIT-JEE, 2012)

The correct options are
A HCl
C HBr
D HI
$A g N O_{3} + H C l \to A g C l ↓$
$A g N O_{3} + H B r \to A g B r ↓$
$A g N O_{3} + H l \to A g I ↓$
All these precipitates will get dissolved in hypo $(N a_{2} S_{2} O_{3})$ forming complex, $N a_{3} [A g (S_{2} O_{3})_{2}]$