The correct option is C R−Cl+NaI→
Bromides and chlorides are insoluble in acetone and hence they can't form a solution with acetone to react with alkyl halides. Sodium iodide, however, is soluble in acetone thus forms a solution with acetone and reacts with alkyl halides, thus undergoing Finkelstein reaction to form corresponding alkyl iodide.
The general reaction is shown below:
Hence, the correct option is 'c'.
C2H5ClEthyl Chloride+NaIDry Acetone−−−−−−−→HeatC2H5IEthyl Iodide+NaCl↓