Which of the following has $2^{n d}$ I.P $<$ $1^{s t}$ I.P?

M g

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N e

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C

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None of the above

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Solution

The correct option is C None of the above
The $2^{n d}$ I.E is always greater than $1^{s t}$ I.E because it requires even more energy to remove an electron from a cation than it neutral atom.

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Similar questions

Correct orders of $1 s t$ I.P. are -

(i) Li < B < Be < C

(ii) O < N < F

(iii) Be < N < Ne

1^{s t}

O_{(g)}

O_{(g)}^{-}

N e_{(g)}

N e_{(g)}^{+}

O_{(g)}^{+}

O_{(g)}

N_{(g)}

N_{(g)}^{+}

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