Which of the following has a high-spin or outer orbital complex?

{[C o {(H_{2} O)}_{6}]}_{6}^{3 +}

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{[C o {(C N)}_{6}]}_{6}^{3 -}

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{[C o F_{6}]}_{6}^{3 -}

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{[F e {(C N)}_{6}]}_{6}^{4 -}

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Solution

The correct option is C ${[C o F_{6}]}_{6}^{3 -}$
Compounds which have weak field ligands form outer orbital complex. Every ligand is strong for $C o^{3 +}$ except fluorine. Hence, ${[C o F_{6}]}_{6}^{3 -}$ is an outer orbital complex.

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Similar questions

Q. Out of

[C o F_{6}]^{3 -}

and

[C o (e n)_{3}]^{3 +}

, which one complex is:
(i) paramagnetic
(ii) more stable
(iii) inner orbital complex and
(iv) high spin complex (Atomic no. of Co = 27)

The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, $[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
$[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
(a) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$
(b) $[C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +}$
(c) $[C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +} > [C o (C N)_{6}]^{3 -}$
(d) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$

Q. Which of these statements about

[C o (C N)_{6}]^{3 -}

is true ?

Q. Select outer d-complexes :

I : [F e (C N)_{6}]^{3 -} I I : [F e (H_{2} O)_{6}]^{2 +}

I I I : [C o F_{6}]^{3 -}

Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following
(a) $[C o F_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{2 +}, [C o (C N)_{6}]^{3 -}$
(b) $F e F_{6}^{3 -}, [F e (H_{2} O)_{6}]^{2 +}, [F e (C N)_{6}]^{4 -}$

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Which of the following has a high-spin or outer orbital complex?

The correct option is C [CoF6]3−Compounds which have weak field ligands form outer orbital complex. Every ligand is strong for Co3+ except fluorine. Hence, [CoF6]3− is an outer orbital complex.

The correct option is C ${[C o F_{6}]}_{6}^{3 -}$
Compounds which have weak field ligands form outer orbital complex. Every ligand is strong for $C o^{3 +}$ except fluorine. Hence, ${[C o F_{6}]}_{6}^{3 -}$ is an outer orbital complex.