Which of the following has a octet/duplet electronic configuration?
A
B3−
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B
B−
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C
B3+
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D
B2+
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Solution
The correct option is CB3+ The atomic number of Boron =5 Electronic configuration of Boron is: [He]2s22p1 Configuration of valence shell: 2s22p1 It does not have a complete octet.
a) B3− Electronic configuration of B3− (with 8 electrons) is: [He]2s22p4 Configuration of valence shell: 2s22p4 It does not have a complete octet.
b) B− Electronic configuration of B− ( with 6 electrons) is: [He]2s22p2 Configuration of valence shell: 2s22p2 It does not have a complete octet.
(c) B3+ Electronic configuration of B3+ (with 2 electrons) is: [He] Configuration of valence shell: 1s2 Boron is most likely to form B3+ as it forms an inert gas electronic configuration of Helium (satisfying duplet).
(d) B2+ Electronic configuration of B2+ ( with 3 electrons) is: [He]2s1 Configuration of valence shell: 2s1 It does not have a complete octet.