Question

Which of the following has an identical bond order?

• A. $C{N}^{-}$
• B. $N{O}^{+}$
• C. Both (a) and (b)
• D. None of these

Answer 1

The correct option is C Both (a) and (b)

Both $C{N}^{-}$ and $N{O}^{+}$ have 14 electrons and their electronic configuration are same.
$\left({\sigma }_{1s}{)}^2\right({\sigma }_{1s}^{\ast }{)}^2\left({\sigma }_{2s}{)}^2\right({\sigma }_{2s}^{\ast }{)}^2\left({\sigma }_{2p_z}{)}^2\right({\pi }_{2p_x}{)}^2({\pi }_{2p_y}{)}^2$

Therefore, their bond orders are same