Which of the following has been arranged in order of decreasing freezing point?

0.05 M K N O_{3} > 0.04 M C a C l_{2} > 0.140 M s u g a r > 0.075 M C u S O_{4}

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0.04 M B a C l_{2} > 0.140 M s u c r o s e > 0.075 M C u S O_{4} > 0.05 M K N O_{3}

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0.75 M C u S O_{4} > 0.140 M s u c r o s e > 0.04 M B a C l_{2} >) .05 M K N O_{3}

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0.075 M C u S O_{4} > 0.05 M N a N O_{3} > 0.140 M s u c r o s e > 0.04 M B a C l_{2}

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Solution

The correct option is A $0.05 M K N O_{3} > 0.04 M C a C l_{2} > 0.140 M s u g a r > 0.075 M C u S O_{4}$
Effective molarity $=$ Given molartiy $\times$ No. of particles per molecule i solution
For 1) $K N O_{3} 0 \cdot 1 M, C a C l_{2} 0 \cdot 12 M, s u g a r 0 \cdot 14 M, C U S O_{4} 0 \cdot 15 M$
Higher the effective molarity, more is the depression in freezing point.
The correct answer is (a)

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