Which of the following has been arranged in the order of decreasing dipole moments?

C H_{3} C l > C H_{3} F > C H_{3} B r > C H_{3} I

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C H_{3} F > C H_{3} C l > C H_{3} B r > C H_{3} I

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C H_{3} C l > C H_{3} B r > C H_{3} I > C H_{3} F

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C H_{3} F > C H_{3} C l > C H_{3} I > C H_{3} B r

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Solution

The correct option is A $C H_{3} C l > C H_{3} F > C H_{3} B r > C H_{3} I$
Greater the value of electronegativity, higher will be the dipole moment. So, $C H F_{3}$ is expected to have greater dipole moment. But, due to extreme smaller size of fluorine, the dipole moment of $C H C l_{3}$ outerweighs that of $C H F_{3}$ . So the order of dipole moment is $C H_{3} C l > C H_{3} F > C H_{3} B r > C H_{3} I$

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