Which of the following has highest boiling point?

C H_{4}

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H_{2} O

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H F

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N H_{3}

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Solution

The correct option is A $H_{2} O$
Due to Hydrogen bonding (inter molecular) Boiling point $↑$
H bond strength $\propto E N$
$\propto \frac{1}{size of atom}$
$H F > H_{2} O > N H_{3}$ H-bond strength
But Boiling point
$H_{2} O > H F > N H_{3}$
$100^{o} C ({19.6}^{o} C)$
$⇓$
In $H_{2} O_{2}$ Hydrogen in volve in H-bonding in HF only one
hydrogen involve in H bonding

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Question 04

Hydrogen bonds are formed in many compounds e.g., $H_{2} O, H F, N H_{3}$ . The boiling point of such compounds depends to a extent on the strength of hydrogen bond and the number of hydrogen bonds. The correct decreasing order of the boiling points above compounds is

(a) $H F > H_{2} O > N H_{3}$

(b) $H_{2} O > H F > N H_{3}$

(d) $N H_{3} > H_{2} O > H F$

The boiling point of NH3 H2O and HF are exceptionally higher explain

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Which of the following has highest boiling point?

The correct option is A H2ODue to Hydrogen bonding (inter molecular) Boiling point ↑H bond strength ∝EN∝1size of atomHF>H2O>NH3 H-bond strengthBut Boiling pointH2O>HF>NH3100oC(19.6oC)⇓In H2O2 Hydrogen in volve in H-bonding in HF only one hydrogen involve in H bonding