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Hydrides of Nitrogen

Which of the ...

Question

Which of the following has highest dipole moment?

N H_{3}

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P H_{3}

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S b H_{3}

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A s H_{3}

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Solution

The correct option is A $N H_{3}$
As we from top to bottom in a group the dipole moment of hydrides of the elements of that particular group decreases dye to increase in the size of the element
So the order of dipole moment of the given hydrides
$N H_{3} > P H_{3} > A s H_{3} > S b H_{3}$
Hence option $A$ is correct.

Suggest Corrections

Similar questions

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

S i F_{4} < S i C l_{4} < S i B r_{4} < S i I_{4}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

N H_{3}, P H_{3}, A s H_{3}

S b H_{3}

N H_{3}, P H_{3}, A s H_{3}, S b H_{3}

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