Question

Which of the following has largest number of oxygen atoms?
$1.0g$ of $O$ atoms, $1.0g$ of $O_2,1.0g$ of ozone $\left(O_3\right)$.
Justify your answer.

Answer 1

$1.0g$ of $O$ atoms $=\frac{1}{16}g$ atoms of $O$
$=\frac{1}{16}\ast 6.02\ast {10}^{23}$ atoms
$=\frac{6.02\ast {10}^{23}}{16}$ atoms
$1.0g$ of $O_2=\frac{1}{32}mol$ of $O_2=\frac{1}{32}\ast 6.02\ast {10}^{23}$
molucles $=2\ast \frac{1}{32}\ast 6.02\ast {10}^{23}$ atoms
$=\frac{6.02\ast {10}^{23}}{16}$ atoms
$1.0g$ of $O_3=\frac{1}{48}mol$ of $O_3=\frac{1}{48}\ast 6.02\ast {10}^{23}$
molucles $=3\ast \frac{1}{48}\ast 6.02\ast {10}^{23}$ atoms
$=\frac{6.02\ast {10}^{23}}{16}$ atoms
Thus, all of them contain equal number of atoms.