Question 6
Which of the following has maximum number of atoms?
(a) $18 g o f H_{2} O$
(b) $18 g o f O_{2}$
(c) $18 g o f C O_{2}$
(d) $18 g o f C H_{4}$

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Solution

$N u m b e r o f a t o m s = \frac{M a s s o f s u b s t a n c e \times N u m b e r o f a t o m s i n t h e m o l e c u l e}{M o l a r m a s s} \times N_{A}$
$∴$
(a) $18 g o f w a t e r = \frac{18 \times 3}{18} \times N_{A} = 3 N_{A}$
(b) $18 g o f o x y g e n = \frac{18 \times 2}{32} \times N_{A} = 1.12 N_{A}$
(c) $18 g o f C O_{2} = \frac{18 \times 3}{44} \times N_{A} = 1.23 N_{A}$
(d) $18 g o f C H_{4} = \frac{18 \times 5}{16} \times N_{A} = 5.63 N_{A}$

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