Question

Which of the following has $p_{\pi }-d_{\pi }$ bonding?

• A. $N{O}_3^{-}$
• B. $S{O}_3^{2-}$
• C. $B{O}_3^{3-}$
• D. $C{O}_3^{2-}$

Answer 1

Answer: (B)

$S{O}_3^{2-}$

$p\pi -p\pi$ bonding: If there is bonding between two atoms where one atom is having one vacant orbital and another is having one lone pair of electrons, then this electron pair is donated to that respective vacant orbital. This type of bonding is called $p\pi -p\pi$ or $p\pi -d\pi$ depending on the orbital to which the electron pair is donated and from which the electron pair is donated.

In the above options $S{O}_3^{-2}$ forms $p\pi -p\pi$ bonding.

Hence option $B$ is correct.