Question

Which of the following has $s{p}^2$ hybridization?

• A. $C{O}_2$
• B. $S{O}_2$
• C. $N_{2}O$
• D. $CO$

Answer 1

Answer: (B)

$S{O}_2$

We can get the idea of hybridization after drawing lewis structures of each.

(1) $C{O}_2$

TVE$=16$ electrons

(Image 1)

Here, C is sp hybridized.

2.$S{O}_2$

TVE$=18$ electrons

(Image 2)

Here, S is $s{p}^2$ hybridized.

3.$N_{2}O$

TVE$=16$ electrons

(Image 3)

In this case, more lewsi structures are possible. But in all N will be sp hybridized

[*This is not always true)

4.$CO$

TVE$=10$ electrons

(Image 4)

Both Cand O are sp hybridized.

$\therefore$ Only $S{O}_2$ is $s{p}^2$ hybridized.