Which of the following has the highest molar conductivity?

[C o (N H_{3})_{6}] C l_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[C o (N H_{3})_{5} C l] C l_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[C o (N H_{3})_{4} C l_{2}] C l_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[C o (N H_{3})_{3} C l_{3}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $[C o (N H_{3})_{6}] C l_{3}$
Higher number of ions ensures higher molar conductivity. On dissociation of $[C o (N H_{3})_{6}] C l_{3}$ , there will be four ions in the solution.

$3 C l^{-}$ and $[C o (N H_{3})_{6}]^{3 +}$

Suggest Corrections

Similar questions

Arrange the following complexes in the increasing order of conductivity of their solution

$[C o (N H_{3})_{3} C l_{3}], [C o (N H_{3})_{4} C l_{2}] C l, [C o (N H_{3})_{6}] C l_{3}, [C o (N H_{3})_{5} C l] C l_{2}$

Q. The correct order of the following complexes according to increasing conductivity of their solutions will be:
(i)

[C o (N H_{3})_{3} C l_{3}]

(ii)

[C o (N H_{3})_{4} C l_{2}] C l

(iii)

[C o (N H_{3})_{6}] C l_{3}

(iv)

[C o (N H_{3})_{5} C l] C l_{2}

Q. Which of the following does not give a precipitate of

A g C l

with

A g N O_{3}

solution?

Q. One mole of the complex with molecular formula

[C o (N H_{3})_{5} C l_{3}]

gives two moles of

A g C l

with excess of

A g N O_{3}

. The complex is

Q. Among the following, which complex compound is diamagnetic?

[C o (N H_{3})_{6}] C l_{3}

,
ii)

[N i (N H_{3})_{6}] C l_{2}

,
iii)

[C r (H_{2} O)_{6}] C l_{3}

,
iv)

[F e (H_{2} O)_{6}] C l_{2}

Join BYJU'S Learning Program

Which of the following has the highest molar conductivity?

The correct option is A [Co(NH3)6]Cl3Higher number of ions ensures higher molar conductivity. On dissociation of [Co(NH3)6]Cl3, there will be four ions in the solution.3Cl− and [Co(NH3)6]3+

The correct option is A $[C o (N H_{3})_{6}] C l_{3}$
Higher number of ions ensures higher molar conductivity. On dissociation of $[C o (N H_{3})_{6}] C l_{3}$ , there will be four ions in the solution.

$3 C l^{-}$ and $[C o (N H_{3})_{6}]^{3 +}$